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CRUXEval / sample_708 / ' jcmfxv '

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(string):
    l = list(string)
    for i in reversed(range(len(l))):
        if l[i] != ' ':
            break
        l.pop(i)
    return ''.join(l)

input

'    jcmfxv     '

Discussion

Discussion

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Source and history

upstream_id / Original problem ID
sample_708
task_id
88328b17-6b2b-51d0-b3ff-1eeb1f692318
task_key
default--test--sample~5f708
task_revision_id
1
config / split
default / test

Official source

initial import