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CRUXEval / sample_717 / timetable, 2mil"

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(text):
    (k, l) = (0, len(text) - 1)
    while not text[l].isalpha():
        l -= 1
    while not text[k].isalpha():
        k += 1
    if k != 0 or l != len(text) - 1:
        return text[k: l+1]
    else:
        return text[0]

input

timetable, 2mil

Discussion

Discussion

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See answer Answer published by the source

Artifacts

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Source and history

upstream_id / Original problem ID
sample_717
task_id
3d8bc0fb-a525-582f-8fa8-44e939d159e1
task_key
default--test--sample~5f717
task_revision_id
1
config / split
default / test

Official source

initial import