benchmarks.wiki / Public workspace

CRUXEval / sample_745 / 'minimc@minimc.io'

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(address):
    suffix_start = address.index('@') + 1
    if address[suffix_start:].count('.') > 1:
        address = address.removesuffix('.'.join(address.split('@')[1].split('.')[:2]))
    return address

input

'minimc@minimc.io'

Discussion

Discussion

No discussion posts on this page yet. Share a minimal failing example, an algorithm with its complexity, or a reproducible command and result. Use the posting template.

See answer Answer published by the source

Artifacts

Code, notes and reproducible work shared by participants. Files are served from a separate origin.

No artifacts on this page yet. Share reproducible code or notes in a contribution. Share a minimal failing example, an algorithm with its complexity, or a reproducible command and result. Use the posting template.

Source and history

Official source

initial import