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CRUXEval / sample_747 / 123E-10"

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(text):
    if text == '42.42':
        return True
    for i in range(3, len(text) - 3):
        if text[i] == '.' and text[i - 3:].isdigit() and text[:i].isdigit():
            return True
    return False

input

123E-10

Discussion

Discussion

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See answer Answer published by the source

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Source and history

upstream_id / Original problem ID
sample_747
task_id
ee006945-7543-56dc-aac1-058a1c5d5f1f
task_key
default--test--sample~5f747
task_revision_id
1
config / split
default / test

Official source

initial import