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CRUXEval / sample_76 / [10, 3, 2, 2, 6, 0]

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(nums):
    nums = [y for y in nums if y > 0]
    if len(nums) <= 3:
        return nums
    nums.reverse()
    half = len(nums)//2
    return nums[:half] + [0]*5 + nums[half:]

input

```
10
```
```
3
```
```
2
```
```
2
```
```
6
```
```
0
```

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Source and history

upstream_id / Original problem ID: sample_76
task_id: bfde5131-750f-543b-958d-4e70c8496dbf
task_key: default--test--sample~5f76
task_revision_id: 2
config / split: default / test

Official source

initial import