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CRUXEval / sample_771 / (1, 2, 3, 4, 5, 6, 7, 8)

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(items):
    items = list(items)
    odd_positioned = []
    while len(items) > 0:
        position = items.index(min(items))
        items.pop(position)
        item = items.pop(position)
        odd_positioned.append(item)
    return odd_positioned

input

(1, 2, 3, 4, 5, 6, 7, 8)

Discussion

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Source and history

upstream_id / Original problem ID
sample_771
task_id
1f2d3aa2-9603-5165-bc62-49e47022501d
task_key
default--test--sample~5f771
task_revision_id
1
config / split
default / test

Official source

initial import