benchmarks.wiki / Public workspace

DS-1000 / 731 / I have two csr_matrix, c1, c2.

Problem

Answer published by the source. Consult the official source to check your work against its answer.

prompt

Problem:
I have two csr_matrix, c1, c2.

I want a new matrix Feature = [c1, c2]. But if I directly concatenate them horizontally this way, there's an error that says the matrix Feature is a list. How can I achieve the matrix concatenation and still get the same type of matrix, i.e. a csr_matrix?

And it doesn't work if I do this after the concatenation: Feature = csr_matrix(Feature) It gives the error:

Traceback (most recent call last):
  File "yelpfilter.py", line 91, in <module>
    Feature = csr_matrix(Feature)
  File "c:\python27\lib\site-packages\scipy\sparse\compressed.py", line 66, in __init__
    self._set_self( self.__class__(coo_matrix(arg1, dtype=dtype)) )
  File "c:\python27\lib\site-packages\scipy\sparse\coo.py", line 185, in __init__
    self.row, self.col = M.nonzero()
TypeError: __nonzero__ should return bool or int, returned numpy.bool_

A:
<code>
from scipy import sparse
c1 = sparse.csr_matrix([[0, 0, 1, 0], [2, 0, 0, 0], [0, 0, 0, 0]])
c2 = sparse.csr_matrix([[0, 3, 4, 0], [0, 0, 0, 5], [6, 7, 0, 8]])
</code>
Feature = ... # put solution in this variable
BEGIN SOLUTION
<code>

library

Scipy

Discussion

Discussion

No discussion posts on this page yet. Share a minimal failing example, an algorithm with its complexity, or a reproducible command and result. Use the posting template.

See answer Answer published by the source

Artifacts

Code, notes and reproducible work shared by participants. Files are served from a separate origin.

No artifacts on this page yet. Share reproducible code or notes in a contribution. Share a minimal failing example, an algorithm with its complexity, or a reproducible command and result. Use the posting template.

Source and history

Official source

initial import