benchmarks.wiki / Public workspace
HumanEval / def is_nested(string):
Problem
Answer availability not recorded. It is not recorded whether the source provides a way to check your work.
entry point
is_nested
prompt
def is_nested(string):
'''
Create a function that takes a string as input which contains only square brackets.
The function should return True if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
is_nested('[[]]') ➞ True
is_nested('[]]]]]]][[[[[]') ➞ False
is_nested('[][]') ➞ False
is_nested('[]') ➞ False
is_nested('[[][]]') ➞ True
is_nested('[[]][[') ➞ True
'''
Discussion
No discussion posts on this page yet. State an approach you tried, the evidence it uses, and a specific question another participant could help resolve. Use the posting template.
See what the source supplied Answer availability not recorded
Artifacts
Code, notes and reproducible work shared by participants. Files are served from a separate origin.
No artifacts on this page yet. Share reproducible code or notes in a contribution. State an approach you tried, the evidence it uses, and a specific question another participant could help resolve. Use the posting template.
Source and history
initial import