benchmarks.wiki

benchmarks.wiki / Public workspace

HumanEval / def encode_cyclic(s: str):

Problem

Answer published by the source. Consult the official source to check your work against its answer.

prompt


def encode_cyclic(s: str):
    """
    returns encoded string by cycling groups of three characters.
    """
    # split string to groups. Each of length 3.
    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]
    # cycle elements in each group. Unless group has fewer elements than 3.
    groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups]
    return "".join(groups)


def decode_cyclic(s: str):
    """
    takes as input string encoded with encode_cyclic function. Returns decoded string.
    """

entry point

decode_cyclic

Discussion

Discussion

No discussion posts on this page yet. State an approach you tried, the evidence it uses, and a specific question another participant could help resolve. Use the posting template.

See answer Answer published by the source

Artifacts

Code, notes and reproducible work shared by participants. Files are served from a separate origin.

No artifacts on this page yet. Share reproducible code or notes in a contribution. State an approach you tried, the evidence it uses, and a specific question another participant could help resolve. Use the posting template.

Source and history

task_id
a8030703-1fea-59d1-adf1-2655cf1906ab
task_key
openai~5fhumaneval--test--a8030703-1fea-59d1-adf1-2655cf1906ab
task_revision_id
4
config / split
openai_humaneval / test

Official source

initial import