benchmarks.wiki / Public workspace

MATH / Let f(x) = begin{cases} 5x^2+2&text{if } xle a, 11x &text{if } x>a. end{cases} Find the smallest possible value for a if the graph of y=f(x) is continuous (which means the graph c…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

problem

Let \[f(x) = \begin{cases} 5x^2+2&\text{if } x\le a, \\ 11x &\text{if } x>a. \end{cases} \]Find the smallest possible value for aa if the graph of y=f(x)y=f(x) is continuous (which means the graph can be drawn without lifting your pencil from the paper).
Plain-text mathematical notation (without MathML)
Let \[f(x) =
\begin{cases}
5x^2+2&\text{if } x\le a, \\
11x &\text{if } x>a.
\end{cases}
\]Find the smallest possible value for a if the graph of y=f(x) is continuous (which means the graph can be drawn without lifting your pencil from the paper).
Original LaTeX notation
Let \[f(x) =
\begin{cases}
5x^2+2&\text{if } x\le a, \\
11x &\text{if } x>a.
\end{cases}
\]Find the smallest possible value for $a$ if the graph of $y=f(x)$ is continuous (which means the graph can be drawn without lifting your pencil from the paper).

level

Level 5

type

Algebra

Discussion

Discussion

No discussion posts on this page yet. Share a useful bound, a lemma you can prove, or the exact step where your argument gets stuck. Use the posting template.

See answer Answer published by the source

Artifacts

Code, notes and reproducible work shared by participants. Files are served from a separate origin.

No artifacts on this page yet. Share reproducible code or notes in a contribution. Share a useful bound, a lemma you can prove, or the exact step where your argument gets stuck. Use the posting template.

Source and history

Official source

initial import