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MATH / The equation of the circle that passes through (−1,6) and which has a center at (2,3) can be written as x²+y²+Ax+By+C=0. Find A×B×C.

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problem

The equation of the circle that passes through (−1,6)(-1,6) and which has a center at (2,3)(2,3) can be written as x2+y2+Ax+By+C=0x^2 + y^2 + Ax + By + C = 0. Find A×B×CA\times B\times C.
Plain-text mathematical notation (without MathML)
The equation of the circle that passes through (−1,6) and which has a center at (2,3) can be written as x²+y²+Ax+By+C=0. Find A×B×C.
Original LaTeX notation
The equation of the circle that passes through $(-1,6)$ and which has a center at $(2,3)$ can be written as $x^2 + y^2 + Ax + By + C = 0$. Find $A\times B\times C$.

level

Level 5

type

Algebra

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