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MATH / In the diagram shown here (which is not drawn to scale), suppose that △ABC∼△PAQ and △ABQ∼△QCP. If m∠BAC=70^(∘), then compute m∠PQC. [asy] size(150); defaultpen(linewidth(0.8)); pai…

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Answer published by the source. Consult the official source to check your work against its answer.

problem

In the diagram shown here (which is not drawn to scale), suppose that △ABC∼△PAQ\triangle ABC \sim \triangle PAQ and △ABQ∼△QCP\triangle ABQ \sim \triangle QCP. If m∠BAC=70∘m\angle BAC = 70^\circ, then compute m∠PQCm\angle PQC. [asy] size(150); defaultpen(linewidth(0.8)); pair B = (0,0), C = (6,0), A = (2,4), Q = (1,0), P = (A + C)/2; draw(A--B--C--A--Q--P); label("BB",B,S); label("AA",A,N); label("CC",C,S); label("PP",P,E); label("QQ",Q,S); [/asy]
Plain-text mathematical notation (without MathML)
In the diagram shown here (which is not drawn to scale), suppose that △ABC∼△PAQ and △ABQ∼△QCP.  If m∠BAC=70^(∘), then compute m∠PQC. [asy]
size(150); defaultpen(linewidth(0.8));
pair B = (0,0), C = (6,0), A = (2,4), Q = (1,0), P = (A + C)/2;
draw(A--B--C--A--Q--P);
label("B",B,S); label("A",A,N); label("C",C,S); label("P",P,E); label("Q",Q,S);
[/asy]
Original LaTeX notation
In the diagram shown here (which is not drawn to scale), suppose that $\triangle ABC \sim \triangle PAQ$ and $\triangle ABQ \sim \triangle QCP$.  If $m\angle BAC = 70^\circ$, then compute $m\angle PQC$. [asy]
size(150); defaultpen(linewidth(0.8));
pair B = (0,0), C = (6,0), A = (2,4), Q = (1,0), P = (A + C)/2;
draw(A--B--C--A--Q--P);
label("$B$",B,S); label("$A$",A,N); label("$C$",C,S); label("$P$",P,E); label("$Q$",Q,S);
[/asy]

level

Level 5

type

Geometry

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Source and history

Official source

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