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MATH / The perimeter of △ABC is 32. If ∠ABC=∠ACB and BC=12, what is the length of AB? [asy] draw((0,0)--(12,0)--(6,10)--cycle,black+linewidth(1)); MarkAngle((12,0),(0,0),(6,10),1,black+li…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

problem

The perimeter of △ABC\triangle ABC is 32.32. If ∠ABC=∠ACB\angle ABC=\angle ACB and BC=12,BC=12, what is the length of $AB?$ [asy] draw((0,0)--(12,0)--(6,10)--cycle,black+linewidth(1)); MarkAngle((12,0),(0,0),(6,10),1,black+linewidth(1)); MarkAngle((6,10),(12,0),(0,0),1,black+linewidth(1)); label("AA",(6,10),N); label("BB",(0,0),W); label("CC",(12,0),E); label("12",(0,0)--(12,0),S); [/asy]
Plain-text mathematical notation (without MathML)
The perimeter of △ABC is 32. If ∠ABC=∠ACB and BC=12, what is the length of $AB?$

[asy]
draw((0,0)--(12,0)--(6,10)--cycle,black+linewidth(1));
MarkAngle((12,0),(0,0),(6,10),1,black+linewidth(1));
MarkAngle((6,10),(12,0),(0,0),1,black+linewidth(1));
label("A",(6,10),N);
label("B",(0,0),W);
label("C",(12,0),E);
label("12",(0,0)--(12,0),S);
[/asy]
Original LaTeX notation
The perimeter of $\triangle ABC$ is $32.$ If $\angle ABC=\angle ACB$ and $BC=12,$ what is the length of $AB?$

[asy]
draw((0,0)--(12,0)--(6,10)--cycle,black+linewidth(1));
MarkAngle((12,0),(0,0),(6,10),1,black+linewidth(1));
MarkAngle((6,10),(12,0),(0,0),1,black+linewidth(1));
label("$A$",(6,10),N);
label("$B$",(0,0),W);
label("$C$",(12,0),E);
label("12",(0,0)--(12,0),S);
[/asy]

level

Level 1

type

Geometry

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Source and history

Official source

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