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MATH / In right triangle ABC, we have ∠BAC=90^(∘) and D is on (AC)¯ such that (BD)¯ bisects ∠ABC. If AB=12 and BC=15, then what is cos∠BDC?

Problem

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problem

In right triangle ABCABC, we have ∠BAC=90∘\angle BAC = 90^\circ and DD is on AC¯\overline{AC} such that BD¯\overline{BD} bisects ∠ABC\angle ABC. If AB=12AB = 12 and BC=15BC = 15, then what is cos∠BDC\cos \angle BDC?
Plain-text mathematical notation (without MathML)
In right triangle ABC, we have ∠BAC=90^(∘) and D is on (AC)¯ such that (BD)¯ bisects ∠ABC. If AB=12 and BC=15, then what is cos∠BDC?
Original LaTeX notation
In right triangle $ABC$, we have $\angle BAC = 90^\circ$ and $D$ is on $\overline{AC}$ such that $\overline{BD}$ bisects $\angle ABC$. If $AB = 12$ and $BC = 15$, then what is $\cos \angle BDC$?

level

Level 5

type

Geometry

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Source and history

task_id
724ce916-ffa2-53a4-acd5-16c601f751d2
task_key
geometry--test--724ce916-ffa2-53a4-acd5-16c601f751d2
task_revision_id
1
config / split
geometry / test

Official source

initial import