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MATH / By joining alternate vertices of a regular hexagon with edges 4 inches long, two equilateral triangles are formed, as shown. What is the area, in square inches, of the region that …

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Answer published by the source. Consult the official source to check your work against its answer.

problem

By joining alternate vertices of a regular hexagon with edges 44 inches long, two equilateral triangles are formed, as shown. What is the area, in square inches, of the region that is common to the two triangles? Express your answer in simplest radical form. [asy] draw((0,3)--(0,8)--(4,11)--(8,8)--(8,3)--(4,0)--cycle,black+linewidth(1)); draw((4,0)--(0,8)--(8,8)--cycle, black+dashed+linewidth(1)); draw((0,3)--(4,11)--(8,3)--cycle, black+dotted+linewidth(1)); label("4",(8,5.5),E); [/asy]
Plain-text mathematical notation (without MathML)
By joining alternate vertices of a regular hexagon with edges 4 inches long, two equilateral triangles are formed, as shown. What is the area, in square inches, of the region that is common to the two triangles? Express your answer in simplest radical form. [asy]
draw((0,3)--(0,8)--(4,11)--(8,8)--(8,3)--(4,0)--cycle,black+linewidth(1));
draw((4,0)--(0,8)--(8,8)--cycle, black+dashed+linewidth(1));
draw((0,3)--(4,11)--(8,3)--cycle, black+dotted+linewidth(1));
label("4",(8,5.5),E);
[/asy]
Original LaTeX notation
By joining alternate vertices of a regular hexagon with edges $4$ inches long, two equilateral triangles are formed, as shown. What is the area, in square inches, of the region that is common to the two triangles? Express your answer in simplest radical form. [asy]
draw((0,3)--(0,8)--(4,11)--(8,8)--(8,3)--(4,0)--cycle,black+linewidth(1));
draw((4,0)--(0,8)--(8,8)--cycle, black+dashed+linewidth(1));
draw((0,3)--(4,11)--(8,3)--cycle, black+dotted+linewidth(1));
label("4",(8,5.5),E);
[/asy]

level

Level 5

type

Geometry

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