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MATH / In right triangle ABC, ∠B=90^(∘), and D and E lie on AC such that (BD)¯ is a median and (BE)¯ is an altitude. If BD=2⋅DE, compute (AB)/(EC). [asy] pair A,B,C,D,E; A=(0,0); C=(2,0);…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

problem

In right triangle ABCABC, ∠B=90∘\angle B = 90^\circ, and DD and EE lie on ACAC such that BD¯\overline{BD} is a median and BE¯\overline{BE} is an altitude. If BD=2⋅DEBD=2\cdot DE, compute ABEC\frac{AB}{EC}. [asy] pair A,B,C,D,E; A=(0,0); C=(2,0); B=(1.5,sqrt(3)/2); D=(1,0); E=(1.5,0); draw(A--B--C--cycle); draw(B--D); draw(B--E); label("AA",A,SW); label("BB",B,N); label("CC",C,SE); label("DD",D,S); label("EE",E,S); draw(rightanglemark(B,E,D,2)); [/asy]
Plain-text mathematical notation (without MathML)
In right triangle ABC, ∠B=90^(∘), and D and E lie on AC such that (BD)¯ is a median and (BE)¯ is an altitude.  If BD=2⋅DE, compute (AB)/(EC). [asy]

pair A,B,C,D,E;

A=(0,0); C=(2,0); B=(1.5,sqrt(3)/2); D=(1,0); E=(1.5,0);

draw(A--B--C--cycle); draw(B--D); draw(B--E);

label("A",A,SW); label("B",B,N); label("C",C,SE); label("D",D,S); label("E",E,S);

draw(rightanglemark(B,E,D,2));

[/asy]
Original LaTeX notation
In right triangle $ABC$, $\angle B = 90^\circ$, and $D$ and $E$ lie on $AC$ such that $\overline{BD}$ is a median and $\overline{BE}$ is an altitude.  If $BD=2\cdot DE$, compute $\frac{AB}{EC}$. [asy]

pair A,B,C,D,E;

A=(0,0); C=(2,0); B=(1.5,sqrt(3)/2); D=(1,0); E=(1.5,0);

draw(A--B--C--cycle); draw(B--D); draw(B--E);

label("$A$",A,SW); label("$B$",B,N); label("$C$",C,SE); label("$D$",D,S); label("$E$",E,S);

draw(rightanglemark(B,E,D,2));

[/asy]

level

Level 5

type

Geometry

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