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MATH / The graph of y=f(x) is shown below.

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Answer published by the source. Consult the official source to check your work against its answer.

problem

The graph of y=f(x)y = f(x) is shown below. [asy] unitsize(0.3 cm); real func(real x) { real y; if (x >= -3 && x <= 0) {y = -2 - x;} if (x >= 0 && x <= 2) {y = sqrt(4 - (x - 2)^2) - 2;} if (x >= 2 && x <= 3) {y = 2*(x - 2);} return(y); } int i, n; for (i = -8; i <= 8; ++i) { draw((i,-8)--(i,8),gray(0.7)); draw((-8,i)--(8,i),gray(0.7)); } draw((-8,0)--(8,0),Arrows(6)); draw((0,-8)--(0,8),Arrows(6)); label("xx", (8,0), E); label("yy", (0,8), N); draw(graph(func,-3,3),red); label("y=f(x)y = f(x)", (4,-3), UnFill); [/asy] Which is the graph of y=f(2x+1)y = f(2x + 1)? [asy] unitsize(0.3 cm); picture[] graf; int i, n; real func(real x) { real y; if (x >= -3 && x <= 0) {y = -2 - x;} if (x >= 0 && x <= 2) {y = sqrt(4 - (x - 2)^2) - 2;} if (x >= 2 && x <= 3) {y = 2*(x - 2);} return(y); } real funca(real x) { return(func(2*x + 1)); } for (n = 1; n <= 5; ++n) { graf[n] = new picture; for (i = -8; i <= 8; ++i) { draw(graf[n],(i,-8)--(i,8),gray(0.7)); draw(graf[n],(-8,i)--(8,i),gray(0.7)); } draw(graf[n],(-8,0)--(8,0),Arrows(6)); draw(graf[n],(0,-8)--(0,8),Arrows(6)); label(graf[n],"xx", (8,0), E); label(graf[n],"yy", (0,8), N); } draw(graf[1],graph(funca,-2,1),red); draw(graf[2],shift((1,0))*xscale(2)*graph(func,-3,3),red); draw(graf[3],shift((1/2,0))*xscale(1/2)*graph(func,-3,3),red); draw(graf[4],shift((-1,0))*xscale(1/2)*graph(func,-3,3),red); draw(graf[5],shift((-1,0))*xscale(2)*graph(func,-3,3),red); label(graf[1], "A", (0,-10)); label(graf[2], "B", (0,-10)); label(graf[3], "C", (0,-10)); label(graf[4], "D", (0,-10)); label(graf[5], "E", (0,-10)); add(graf[1]); add(shift((20,0))*(graf[2])); add(shift((40,0))*(graf[3])); add(shift((10,-20))*(graf[4])); add(shift((30,-20))*(graf[5])); [/asy] Enter the letter of the graph of y=f(2x+1).y = f(2x + 1).
Plain-text mathematical notation (without MathML)
The graph of y=f(x) is shown below.

[asy]
unitsize(0.3 cm);

real func(real x) {
  real y;
  if (x >= -3 && x <= 0) {y = -2 - x;}
  if (x >= 0 && x <= 2) {y = sqrt(4 - (x - 2)^2) - 2;}
  if (x >= 2 && x <= 3) {y = 2*(x - 2);}
  return(y);
}

int i, n;

for (i = -8; i <= 8; ++i) {
  draw((i,-8)--(i,8),gray(0.7));
  draw((-8,i)--(8,i),gray(0.7));
}

draw((-8,0)--(8,0),Arrows(6));
draw((0,-8)--(0,8),Arrows(6));

label("x", (8,0), E);
label("y", (0,8), N);

draw(graph(func,-3,3),red);

label("y=f(x)", (4,-3), UnFill);
[/asy]

Which is the graph of y=f(2x+1)?

[asy]
unitsize(0.3 cm);

picture[] graf;
int i, n;

real func(real x) {
  real y;
  if (x >= -3 && x <= 0) {y = -2 - x;}
  if (x >= 0 && x <= 2) {y = sqrt(4 - (x - 2)^2) - 2;}
  if (x >= 2 && x <= 3) {y = 2*(x - 2);}
  return(y);
}

real funca(real x) {
  return(func(2*x + 1));
}

for (n = 1; n <= 5; ++n) {
  graf[n] = new picture;
  for (i = -8; i <= 8; ++i) {
    draw(graf[n],(i,-8)--(i,8),gray(0.7));
    draw(graf[n],(-8,i)--(8,i),gray(0.7));
  }
  draw(graf[n],(-8,0)--(8,0),Arrows(6));
  draw(graf[n],(0,-8)--(0,8),Arrows(6));

  label(graf[n],"x", (8,0), E);
  label(graf[n],"y", (0,8), N);
}

draw(graf[1],graph(funca,-2,1),red);
draw(graf[2],shift((1,0))*xscale(2)*graph(func,-3,3),red);
draw(graf[3],shift((1/2,0))*xscale(1/2)*graph(func,-3,3),red);
draw(graf[4],shift((-1,0))*xscale(1/2)*graph(func,-3,3),red);
draw(graf[5],shift((-1,0))*xscale(2)*graph(func,-3,3),red);

label(graf[1], "A", (0,-10));
label(graf[2], "B", (0,-10));
label(graf[3], "C", (0,-10));
label(graf[4], "D", (0,-10));
label(graf[5], "E", (0,-10));

add(graf[1]);
add(shift((20,0))*(graf[2]));
add(shift((40,0))*(graf[3]));
add(shift((10,-20))*(graf[4]));
add(shift((30,-20))*(graf[5]));
[/asy]

Enter the letter of the graph of y=f(2x+1).
Original LaTeX notation
The graph of $y = f(x)$ is shown below.

[asy]
unitsize(0.3 cm);

real func(real x) {
  real y;
  if (x >= -3 && x <= 0) {y = -2 - x;}
  if (x >= 0 && x <= 2) {y = sqrt(4 - (x - 2)^2) - 2;}
  if (x >= 2 && x <= 3) {y = 2*(x - 2);}
  return(y);
}

int i, n;

for (i = -8; i <= 8; ++i) {
  draw((i,-8)--(i,8),gray(0.7));
  draw((-8,i)--(8,i),gray(0.7));
}

draw((-8,0)--(8,0),Arrows(6));
draw((0,-8)--(0,8),Arrows(6));

label("$x$", (8,0), E);
label("$y$", (0,8), N);

draw(graph(func,-3,3),red);

label("$y = f(x)$", (4,-3), UnFill);
[/asy]

Which is the graph of $y = f(2x + 1)$?

[asy]
unitsize(0.3 cm);

picture[] graf;
int i, n;

real func(real x) {
  real y;
  if (x >= -3 && x <= 0) {y = -2 - x;}
  if (x >= 0 && x <= 2) {y = sqrt(4 - (x - 2)^2) - 2;}
  if (x >= 2 && x <= 3) {y = 2*(x - 2);}
  return(y);
}

real funca(real x) {
  return(func(2*x + 1));
}

for (n = 1; n <= 5; ++n) {
  graf[n] = new picture;
  for (i = -8; i <= 8; ++i) {
    draw(graf[n],(i,-8)--(i,8),gray(0.7));
    draw(graf[n],(-8,i)--(8,i),gray(0.7));
  }
  draw(graf[n],(-8,0)--(8,0),Arrows(6));
  draw(graf[n],(0,-8)--(0,8),Arrows(6));

  label(graf[n],"$x$", (8,0), E);
  label(graf[n],"$y$", (0,8), N);
}

draw(graf[1],graph(funca,-2,1),red);
draw(graf[2],shift((1,0))*xscale(2)*graph(func,-3,3),red);
draw(graf[3],shift((1/2,0))*xscale(1/2)*graph(func,-3,3),red);
draw(graf[4],shift((-1,0))*xscale(1/2)*graph(func,-3,3),red);
draw(graf[5],shift((-1,0))*xscale(2)*graph(func,-3,3),red);

label(graf[1], "A", (0,-10));
label(graf[2], "B", (0,-10));
label(graf[3], "C", (0,-10));
label(graf[4], "D", (0,-10));
label(graf[5], "E", (0,-10));

add(graf[1]);
add(shift((20,0))*(graf[2]));
add(shift((40,0))*(graf[3]));
add(shift((10,-20))*(graf[4]));
add(shift((30,-20))*(graf[5]));
[/asy]

Enter the letter of the graph of $y = f(2x + 1).$

level

Level 3

type

Intermediate Algebra

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Official source

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