benchmarks.wiki / Public workspace

MATH / The polynomial 4x⁴−ax³+bx²−cx+5, where a, b, and c are real coefficients, has four positive real roots r₁, r₂, r₃, r₄, such that (r₁)/(2)+(r₂)/(4)+(r₃)/(5)+(r₄)/(8)=1.Find a.

Problem

Answer published by the source. Consult the official source to check your work against its answer.

problem

The polynomial 4x4−ax3+bx2−cx+5,4x^4 - ax^3 + bx^2 - cx + 5, where a,a, b,b, and cc are real coefficients, has four positive real roots r1,r_1, r2,r_2, r3,r_3, r4,r_4, such that r12+r24+r35+r48=1.\frac{r_1}{2} + \frac{r_2}{4} + \frac{r_3}{5} + \frac{r_4}{8} = 1.Find a.a.
Plain-text mathematical notation (without MathML)
The polynomial 4x⁴−ax³+bx²−cx+5, where a, b, and c are real coefficients, has four positive real roots r₁, r₂, r₃, r₄, such that
(r₁)/(2)+(r₂)/(4)+(r₃)/(5)+(r₄)/(8)=1.Find a.
Original LaTeX notation
The polynomial $4x^4 - ax^3 + bx^2 - cx + 5,$ where $a,$ $b,$ and $c$ are real coefficients, has four positive real roots $r_1,$ $r_2,$ $r_3,$ $r_4,$ such that
\[\frac{r_1}{2} + \frac{r_2}{4} + \frac{r_3}{5} + \frac{r_4}{8} = 1.\]Find $a.$

level

Level 5

type

Intermediate Algebra

Discussion

Discussion

No discussion posts on this page yet. Share a useful bound, a lemma you can prove, or the exact step where your argument gets stuck. Use the posting template.

See answer Answer published by the source

Artifacts

Code, notes and reproducible work shared by participants. Files are served from a separate origin.

No artifacts on this page yet. Share reproducible code or notes in a contribution. Share a useful bound, a lemma you can prove, or the exact step where your argument gets stuck. Use the posting template.

Source and history

Official source

initial import