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MATH / In right triangle ABC, we have AB=10, BC=24, and ∠ABC=90^(∘). If M is on (AC)¯ such that (BM)¯ is a median of △ABC, then what is cos∠ABM?

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problem

In right triangle ABCABC, we have AB=10AB = 10, BC=24BC = 24, and ∠ABC=90∘\angle ABC = 90^\circ. If MM is on AC¯\overline{AC} such that BM¯\overline{BM} is a median of △ABC\triangle ABC, then what is cos∠ABM\cos \angle ABM?
Plain-text mathematical notation (without MathML)
In right triangle ABC, we have AB=10, BC=24, and ∠ABC=90^(∘). If M is on (AC)¯ such that (BM)¯ is a median of △ABC, then what is cos∠ABM?
Original LaTeX notation
In right triangle $ABC$, we have $AB = 10$, $BC = 24$, and $\angle ABC = 90^\circ$. If $M$ is on $\overline{AC}$ such that $\overline{BM}$ is a median of $\triangle ABC$, then what is $\cos \angle ABM$?

level

Level 2

type

Precalculus

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