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MMLU-Pro / 11571 / Two thousand signals are sampled atNyquistrate by the sampling function S(t) = I…

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question

Two thousand signals are sampled atNyquistrate by the sampling function S(t) = I ^\infty\sum_n=-\infty [t - (1 /f_s) n] wheref_sis the sampling rate. The signals are then time-division multiplexed. If each signal has a bandwidth of 5 kHz, calculate the sampling time T_s and determine\tau_maxfor pulses of duration \tau. (i. e. , stretched impulses).

category

engineering

options

  1. T_s = 2 × 10^-3 sec, \tau_max = 1.0 × 10^-6 sec
  2. T_s = 1 × 10^-2 sec, au_max = 0.5 × 10^-5 sec
  3. T_s = 2 × 10^-4 sec, \tau_max = 1.0 × 10^-7 sec
  4. T_s = 1.5 × 10^-4 sec, \tau_max = 0.75 × 10^-7 sec
  5. T_s = 1 × 10^-4 sec, au_max = 0.5 × 10^-7 sec
  6. T_s = 1 × 10^-5 sec, au_max = 0.5 × 10^-8 sec
  7. T_s = 3 × 10^-4 sec, \tau_max = 1.5 × 10^-7 sec
  8. T_s = 5 × 10^-5 sec, \tau_max = 2.5 × 10^-8 sec
  9. T_s = 1 × 10^-3 sec, au_max = 0.5 × 10^-6 sec
  10. T_s = 8 × 10^-5 sec, \tau_max = 4.0 × 10^-8 sec

src

stemez-ElectronicCommunications

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