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Problem

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question

If the power transfer function of a system is given as \vertH(\omega)\vert^2 = [1 / {1 + (\omega / B)^2}], determine its noise bandwidth, B_N. Note: B is the 3-dB bandwidth in radians/second and \omega is the angular frequency.

category

engineering

options

  1. B_N is equal to the square root of the system 3-dB bandwidth
  2. B_N is equal to the system 3-dB bandwidth
  3. B_N is 1.57 times larger than the system 3-dB bandwidth
  4. B_N is 1.5 times smaller than the system 3-dB bandwidth
  5. B_N is 0.77 times smaller than the system 3-dB bandwidth
  6. B_N is half the system 3-dB bandwidth
  7. B_N is inversely proportional to the system 3-dB bandwidth
  8. B_N is directly proportional to the square of the system 3-dB bandwidth

src

stemez-ElectronicCommunications

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