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MMLU-Pro / 11836 / The inductance of linear time-varying inductor is given by L(t) = L_0(t +tanht)…

Problem

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question

The inductance of linear time-varying inductor is given by L(t) = L_0(t +tanht) and the current through it is given by i (t) =cos\omegat Find the voltage across this inductor.

category

engineering

options

  1. U(t) = L_0 (1 - tanht)cos\omegat + \omegaL_0 (t - sech^2t)sin\omegat
  2. U(t) = L_0 (1 + sech^2t)cos\omegat+ \omegaL_0 (t +tanht)sin\omegat
  3. U(t) = L_0 (1 + sech^2t)cos\omegat- \omegaL_0 (t +tanht)sin\omegat
  4. U(t) = L_0 (1 - sech^2t)cos\omegat- \omegaL_0 (t +tanht)sin\omegat
  5. U(t) = -L_0 (1 + sech^2t)sin\omegat + \omegaL_0 (t + tanht)cos\omegat
  6. U(t) = L_0 (1 + tanht)cos\omegat - \omegaL_0 (t - sech^2t)sin\omegat
  7. U(t) = L_0 (1 + tanht)sin\omegat - \omegaL_0 (t + sech^2t)cos\omegat
  8. U(t) = L_0 (1 - sech^2t)sin\omegat + \omegaL_0 (t + tanht)cos\omegat
  9. U(t) = L_0 (2 + tanht)cos\omegat - \omegaL_0 sech^2t sin\omegat
  10. U(t) = L_0 (1 + sech^2t)sin\omegat- \omegaL_0 (t +tanht)cos\omegat

src

stemez-ElectricCircuits

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Source and history

upstream_id / Original problem ID
11836
task_id
064b9e88-58b6-5e38-be80-2091dccf8161
task_key
default--test--11836
task_revision_id
1
config / split
default / test

Official source

initial import