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MMLU-Pro / 12009 / A voltage of 25…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

A voltage of 25\angle45° Vis applied to an impedance of 4 - j2\Omega. Determine the current in both rectangular and polar forms.

category

engineering

options

  1. 2.5∠45°A in polar form and 2.5 + j2.5A in rectangular form
  2. 2.5√5∠71.6°A in polar form and 1.25√2 + j3.75√2A in rectangular form
  3. 3.54∠-45°A in polar form and 2.5 - j2.5A in rectangular form
  4. 6.25∠45°A in polar form and 3.125 + j4.42A in rectangular form
  5. 5.0∠34.2°A in polar form and 4.0 + j2.5A in rectangular form
  6. 2.5√5∠71.6°A in polar form and 1.35√2 + j3.75√2A in rectangular form
  7. 1.5√5∠71.6°A in polar form and 1.25√2 + j3.75√2A in rectangular form
  8. 4.47∠56.3°A in polar form and 2.5 + j3.89A in rectangular form
  9. 2.5√3∠30°A in polar form and 2.165 + j1.25A in rectangular form
  10. 2.5√5∠51.6°A in polar form and 1.25√2 + j3.75√2A in rectangular form

src

stemez-ElectricCircuits

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Source and history

upstream_id / Original problem ID
12009
task_id
cd7ee10f-eac5-5224-a622-4f4dd6482032
task_key
default--test--12009
task_revision_id
1
config / split
default / test

Official source

initial import