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MMLU-Pro / 12019 / Obtain the time function corresponding to F(s) = [(s^2 + 3s + 1) / (s + 1)^3 (s…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

Obtain the time function corresponding to F(s) = [(s^2 + 3s + 1) / {(s + 1)^3 (s + 2)^2}]

category

engineering

options

  1. F(t) = - (3/2) t^2e^-t + 5te^-t - 6e^-t + (2/3)te^-2t + 3e^-2t
  2. F(t) = (1/3) t^2e^-t - te^-t + e^-t - (2/3)te^-2t - 3e^-2t
  3. F(t) = e^-t - 2te^-t + (1/2) t^2e^-t - e^-2t + (1/2)te^-2t
  4. F(t) = - (1/2) t^2e^-t + 3te^-t - 4e^-t + te^-2t + 4e^-2t
  5. F(t) = - (1/2) t^2e^-t + 3te^-t - 4e^-t - te^-2t - 4e^-2t
  6. F(t) = - (1/2) t^2e^-t - 3te^-t + 4e^-t - te^-2t + 4e^-2t
  7. F(t) = - t^2e^-t + 4te^-t - 5e^-t + 2te^-2t + 5e^-2t
  8. F(t) = (1/2) t^2e^-t + 3te^-t + 4e^-t + te^-2t + 4e^-2t
  9. F(t) = (1/2) t^2e^-t - 3te^-t + 4e^-t - (3/2)te^-2t - 6e^-2t
  10. F(t) = - (1/4) t^2e^-t + 2te^-t - 3e^-t + (1/2)te^-2t + 2e^-2t

src

stemez-ElectricCircuits

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Source and history

upstream_id / Original problem ID
12019
task_id
36bcc149-a055-5428-8428-4bb32b4d9f25
task_key
default--test--12019
task_revision_id
1
config / split
default / test

Official source

initial import