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MMLU-Pro / 12171 / Consider an example of forced convection within a pipe. The local heat transfer…

Problem

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question

Consider an example of forced convection within a pipe. The local heat transfer coefficient is valid at the point it is evaluated at, and in its immediate vicinity. When the length of pipe as a whole is of concern, the average heat transfer coefficient applies. The average temperature difference is defined as (T_s - T)_av= [{(T_s - T_in) + (T_s - T_out)} / 2] where T_s = wall surface temperature T_in = bulk fluid temperature at entrance T_out = bulk fluid temperature at exit. Derive the average heat transfer coefficienth_avin terms of the local coefficienth_x.

category

engineering

options

  1. h_av= [{^L\int_0h_x(T_s - T)dx} / 2\piR^ L]
  2. h_av= [{^L\int_0h_x(T_s - T)dx} / (T_s -T_av)]
  3. h_av= [{^L\int_0h_xdx} / (T_s - T_av)]
  4. h_av= [{^L\int_0h_x(T_s - T)^2dx} / (T_s - T_av)]
  5. h_av= [{^L\int_0h_x(T_s - T)dx} / (T_s + T_av)]
  6. h_av= [{^L\int_0h_x(T_s - T)dx} / (T_in - T_out)]
  7. h_av= [{^L\int_0(h_x + T)dx} / (T_s - T_av)]
  8. h_av= [{^L\int_0h_x(T_s - T)dx} / {(T_s - T_in) + (T_s - T_out)}]
  9. h_av= [{^L\int_0h_x(T_s + T)dx} / (T_s -T_av)]
  10. h_av= [{^L\int_0h_x(T_s - T)dx} / L]

src

stemez-HeatTransfer

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Source and history

upstream_id / Original problem ID
12171
task_id
ade5bfe3-859b-5ac5-b8df-3b7fb0598ffd
task_key
default--test--12171
task_revision_id
1
config / split
default / test

Official source

initial import