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MMLU-Pro / 3819 / The NOF molecule is an asymmetric rotor with rotational constants …

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

The NOF molecule is an asymmetric rotor with rotational constants $3.1752 \mathrm{~cm}^{-1}, 0.3951 \mathrm{~cm}^{-1}$, and $0.3505 \mathrm{~cm}^{-1}$. Calculate the rotational partition function of the molecule at 25∘C25^{\circ} \mathrm{C}.
Plain-text mathematical notation (without MathML)
The NOF molecule is an asymmetric rotor with rotational constants $3.1752 \mathrm{~cm}^{-1}, 0.3951 \mathrm{~cm}^{-1}$, and $0.3505 \mathrm{~cm}^{-1}$. Calculate the rotational partition function of the molecule at 25^(∘)C.
Original LaTeX notation
The NOF molecule is an asymmetric rotor with rotational constants $3.1752 \mathrm{~cm}^{-1}, 0.3951 \mathrm{~cm}^{-1}$, and $0.3505 \mathrm{~cm}^{-1}$. Calculate the rotational partition function of the molecule at $25^{\circ} \mathrm{C}$.

category

chemistry

options

  1. 6.89$10^3$
  2. 7.97$10^3$
  3. 8.72$10^3$
  4. 8.88$10^3$
  5. 5.30$10^3$
  6. 7.50$10^3$
  7. 6.45$10^3$
  8. 9.15$10^3$
  9. 1.02$10^3$
  10. 8.01$10^4$

src

scibench-matter

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Source and history

Official source

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