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Problem

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question

A perfect gas undergoes isothermal compression, which reduces its volume by 2.20dm32.20 \mathrm{dm}^3. The final pressure and volume of the gas are 5.04bar5.04 \mathrm{bar} and 4.65dm34.65 \mathrm{dm}^3, respectively. Calculate the original pressure of the gas in atm.
Plain-text mathematical notation (without MathML)
A perfect gas undergoes isothermal compression, which reduces its volume by 2.20dm³. The final pressure and volume of the gas are 5.04bar and 4.65dm³, respectively. Calculate the original pressure of the gas in atm.
Original LaTeX notation
A perfect gas undergoes isothermal compression, which reduces its volume by $2.20 \mathrm{dm}^3$. The final pressure and volume of the gas are $5.04 \mathrm{bar}$ and $4.65 \mathrm{dm}^3$, respectively. Calculate the original pressure of the gas in atm.

category

chemistry

options

  1. 5.55 atm
  2. 3.38$\mathrm{atm}$
  3. 4.96 $\mathrm{atm}$
  4. 7.03 atm
  5. 1.74 $\mathrm{atm}$
  6. 4.10 atm
  7. 1.01 atm
  8. 2.81 $\mathrm{atm}$
  9. 6.89 atm
  10. 2.22 atm

src

scibench-atkins

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