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MMLU-Pro / 3894 / A silyl radical bearing an Si-H· fragment has a g value of 2.0033 and a pair of…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

A silyl radical bearing an Si-H· fragment has a g value of 2.0033 and a pair of lines separated by 15.5 MHz. Express the splitting in units of mT, Gauss and cm-1.

category

chemistry

options

  1. 15.5 MHz = 0.553 mT = 5.530 Gauss = 5.17 x 10^-4 cm-1
  2. 15.5 MHz = 7.352 mT = 10.104 Gauss = 18.39 x 10^-4 cm-1
  3. 15.5 MHz = 11.104 mT = 27.201 Gauss = 0.862 x 10^-4 cm-1
  4. 15.5 MHz = 0.103 mT = 0.201 Gauss = 2.62 x 10^-4 cm-1
  5. 15.5 MHz = 8.352 mT = 11.104 Gauss = 25.39 x 10^-4 cm-1
  6. 15.5 MHz = 10.553 mT = 20.530 Gauss = 10.17 x 10^-4 cm-1
  7. 15.5 MHz = 2.003 mT = 3.003 Gauss = 21.0 x 10^-4 cm-1
  8. 15.5 MHz = 1.55 mT = 0.562 Gauss = 31.0 x 10^-4 cm-1
  9. 15.5 MHz = 5.55 mT = 15.0 Gauss = 5.5 x 10^-4 cm-1
  10. 15.5 MHz = 3.752 mT = 7.104 Gauss = 1.39 x 10^-4 cm-1

src

ori_mmlu-college_chemistry

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Source and history

upstream_id / Original problem ID
3894
task_id
31402bca-6fc4-5627-99b0-e8d71d152809
task_key
default--test--3894
task_revision_id
1
config / split
default / test

Official source

initial import