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MMLU-Pro / 403 / The daily cost of producing n Gaped Ghouls at the Star Toys Factory is C(n) =…

Problem

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question

The daily cost of producing n Gaped Ghouls at the Star Toys Factory is C(n) = 0.2n^2 + n + 900 where C(n) is in dollars. It has been found that t^2 + 100t Caped Ghouls can be produced in t hours. What is the formula for the rate of change of the total cost with respect to time?

category

business

options

  1. 0.6t + 1
  2. 1.6t^3 + 240t^2 + 8004t + 200
  3. 0.8nt + 40n + 2t + 100
  4. 0.6t^3 + 60t^2 + 300t + 100
  5. 0.4t^2 + 20t + 900
  6. 0.8t^3 + 80t^2 + 40t^2 + 4000t + 2t + 100
  7. 0.2t^2 + 100t + 1
  8. 0.4n + 1
  9. 0.4t^3 + 200t^2 + 100t
  10. 0.8t^3 + 120t^2 + 4002t + 100

src

stemez-Business

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Source and history

upstream_id / Original problem ID
403
task_id
8952dbdf-89ba-573b-8051-8dc9ac67c38c
task_key
default--test--403
task_revision_id
1
config / split
default / test

Official source

initial import