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MMLU-Pro / 4061 / Find an expression for the hydrolysis constant of the bicarbonate ion…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

Find an expression for the hydrolysis constant of the bicarbonate ion HCO_3^-,K_h(HCO_3^-), using only the first dissociation constant for H_2CO_3, K_(a)1 (H_2CO_3), and the water constant, K_W .

category

chemistry

options

  1. K_h(HCO_3^-) = (K_W)^2 * K_(a)1 (H_2CO_3)
  2. K_h(HCO_3^-) = [(K_W)^2/{K_(a)1 (H_2CO_3)}]
  3. K_h(HCO_3^-) = {K_(a)1 (H_2CO_3)}/K_W
  4. K_h(HCO_3^-) = 1/{K_W*K_(a)1 (H_2CO_3)}
  5. K_h(HCO_3^-) = [(K_W)+{K_(a)1 (H_2CO_3)}]
  6. K_h(HCO_3^-) = K_W/{(K_(a)1 (H_2CO_3))^2}
  7. K_h(HCO_3^-) = (K_W + K_(a)1 (H_2CO_3))^2
  8. K_h(HCO_3^-) = [(K_W)/{K_(a)1 (H_2CO_3)}]
  9. K_h(HCO_3^-) = K_(a)1 (H_2CO_3)*K_W
  10. K_h(HCO_3^-) = [(K_W)*{K_(a)1 (H_2CO_3)}]

src

stemez-Chemistry

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Source and history

upstream_id / Original problem ID
4061
task_id
5c538101-2618-5ac1-b5ba-7a577ea1125a
task_key
default--test--4061
task_revision_id
1
config / split
default / test

Official source

initial import