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MMLU-Pro / 4096 / Example 5-3 shows that a Maclaurin expansion of a Morse potential leads to

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

Example 5-3 shows that a Maclaurin expansion of a Morse potential leads to V(x)=Dβ2x2+⋯ V(x)=D \beta^2 x^2+\cdots Given that $D=7.31 \times 10^{-19} \mathrm{~J} \cdot$ molecule −1{ }^{-1} and $\beta=1.81 \times 10^{10} \mathrm{~m}^{-1}$ for HCl\mathrm{HCl}, calculate the force constant of HCl\mathrm{HCl}.
Plain-text mathematical notation (without MathML)
Example 5-3 shows that a Maclaurin expansion of a Morse potential leads to
V(x)=Dβ²x²+⋯
Given that $D=7.31 \times 10^{-19} \mathrm{~J} \cdot$ molecule ^(−1) and $\beta=1.81 \times 10^{10} \mathrm{~m}^{-1}$ for HCl, calculate the force constant of HCl.
Original LaTeX notation
Example 5-3 shows that a Maclaurin expansion of a Morse potential leads to
$$
V(x)=D \beta^2 x^2+\cdots
$$
Given that $D=7.31 \times 10^{-19} \mathrm{~J} \cdot$ molecule ${ }^{-1}$ and $\beta=1.81 \times 10^{10} \mathrm{~m}^{-1}$ for $\mathrm{HCl}$, calculate the force constant of $\mathrm{HCl}$.

category

chemistry

options

  1. 350$\mathrm{~N} \cdot \mathrm{m}^{-1}$
  2. 450$\mathrm{~N} \cdot \mathrm{m}^{-1}$
  3. 490$\mathrm{~N} \cdot \mathrm{m}^{-1}$
  4. 520$\mathrm{~N} \cdot \mathrm{m}^{-1}$
  5. 392$\mathrm{~N} \cdot \mathrm{m}^{-1}$
  6. 600$\mathrm{~N} \cdot \mathrm{m}^{-1}$
  7. 650$\mathrm{~N} \cdot \mathrm{m}^{-1}$
  8. 530$\mathrm{~N} \cdot \mathrm{m}^{-1}$
  9. 479$\mathrm{~N} \cdot \mathrm{m}^{-1}$
  10. 560$\mathrm{~N} \cdot \mathrm{m}^{-1}$

src

scibench-chemmc

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Source and history

Official source

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