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MMLU-Pro / 4229 / In order for a photon of light incident upon metallic potassium to eliminate an…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

In order for a photon of light incident upon metallic potassium to eliminate an electron from it, the photon must have a minimum energy of 4.33eV(photoelectric work function for potassium). What is the wavelength of a photon of this energy? Assume h = 6.626 × 10^-27 erg-sec and c = 2.998 × 10^10 cm/sec.

category

chemistry

options

  1. 2000 Å
  2. 2500 \AA
  3. 2864 \AA
  4. 2200 Å
  5. 4500 Å
  6. 3400 Å
  7. 3700 Å
  8. 3000 \AA
  9. 4000 Å
  10. 3200 \AA

src

stemez-Chemistry

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