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Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

Electron diffraction makes use of electrons with wavelengths comparable to bond lengths. To what speed must an electron be accelerated for it to have a wavelength of 100pm100 \mathrm{pm} ?
Plain-text mathematical notation (without MathML)
Electron diffraction makes use of electrons with wavelengths comparable to bond lengths. To what speed must an electron be accelerated for it to have a wavelength of 100pm ? 
Original LaTeX notation
Electron diffraction makes use of electrons with wavelengths comparable to bond lengths. To what speed must an electron be accelerated for it to have a wavelength of $100 \mathrm{pm}$ ? 

category

chemistry

options

  1. 9.45 $10^6 \mathrm{~m} \mathrm{~s}^{-1}$
  2. 4.89 $10^6 \mathrm{~m} \mathrm{~s}^{-1}$
  3. 3.14 $10^6 \mathrm{~m} \mathrm{~s}^{-1}$
  4. 5.38 $10^6 \mathrm{~m} \mathrm{~s}^{-1}$
  5. 12.67 $10^6 \mathrm{~m} \mathrm{~s}^{-1}$
  6. 7.27 $10^6 \mathrm{~m} \mathrm{~s}^{-1}$
  7. 6.22 $10^6 \mathrm{~m} \mathrm{~s}^{-1}$
  8. 10.33 $10^6 \mathrm{~m} \mathrm{~s}^{-1}$
  9. 8.11 $10^6 \mathrm{~m} \mathrm{~s}^{-1}$
  10. 11.00 $10^6 \mathrm{~m} \mathrm{~s}^{-1}$

src

scibench-matter

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Source and history

Official source

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