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MMLU-Pro / 4305 / The equation for the burning of naphthalene is C_10H_8 (s) + 12O_2(g)…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

The equation for the burning of naphthalene is C_10H_8 (s) + 12O_2(g) \rightarrow1OCO_2 + 4H_2 O (l). For every mole of C_10H_8 burned, - 1226.7 Kcal is evolved at 25° in a fixed- volume combustion chamber. ∆H° for H_2O(l) = - 64.4 Kcal/mole and H_2O (g) = - 57.8 Kcal/mole. Calculate (a) the heat of reaction at constant temperature and (b) ∆H for the case where all of the H_2O is gaseous.

category

chemistry

options

  1. - 1200 Kcal/mole, - 1150 Kcal/mole
  2. - 1250 Kcal/mole, - 1230 Kcal/mole
  3. - 1227.9 Kcal/mole, - 1185.5 Kcal/mole
  4. - 1226.7 Kcal/mole, - 1185.5 Kcal/mole
  5. - 1300 Kcal/mole, - 1200 Kcal/mole
  6. - 1235 Kcal/mole, - 1210 Kcal/mole
  7. - 1226.7 Kcal/mole, - 1200 Kcal/mole
  8. - 1190 Kcal/mole, - 1150 Kcal/mole
  9. - 1227.9 Kcal/mole, - 1200 Kcal/mole
  10. - 1280 Kcal/mole, - 1250 Kcal/mole

src

stemez-Chemistry

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Source and history

upstream_id / Original problem ID
4305
task_id
c559db7e-6e2c-5ad9-9121-1bfdf9f2d623
task_key
default--test--4305
task_revision_id
1
config / split
default / test

Official source

initial import