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MMLU-Pro / 4353 / When alkali metals dissolve in liquid ammonia, their atoms each lose an electron…

Problem

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question

When alkali metals dissolve in liquid ammonia, their atoms each lose an electron and give rise to a deep-blue solution that contains unpaired electrons occupying cavities in the solvent. These 'metal-ammonia solutions' have a maximum absorption at $1500 \mathrm{~nm}$. Supposing that the absorption is due to the excitation of an electron in a spherical square well from its ground state to the next-higher state (see the preceding problem for information), what is the radius of the cavity?
Plain-text mathematical notation (without MathML)
When alkali metals dissolve in liquid ammonia, their atoms each lose an electron and give rise to a deep-blue solution that contains unpaired electrons occupying cavities in the solvent. These 'metal-ammonia solutions' have a maximum absorption at $1500 \mathrm{~nm}$. Supposing that the absorption is due to the excitation of an electron in a spherical square well from its ground state to the next-higher state (see the preceding problem for information), what is the radius of the cavity?
Original LaTeX notation
When alkali metals dissolve in liquid ammonia, their atoms each lose an electron and give rise to a deep-blue solution that contains unpaired electrons occupying cavities in the solvent. These 'metal-ammonia solutions' have a maximum absorption at $1500 \mathrm{~nm}$. Supposing that the absorption is due to the excitation of an electron in a spherical square well from its ground state to the next-higher state (see the preceding problem for information), what is the radius of the cavity?

category

chemistry

options

  1. 0.45 nm
  2. 0.89 $\mathrm{~nm}$
  3. 0.75 $\mathrm{~nm}$
  4. 0.69 $\mathrm{~nm}$
  5. 0.99 nm
  6. 1.25 nm
  7. 0.62 nm
  8. 0.30 nm
  9. 0.54 $\mathrm{~nm}$
  10. 1.10 nm

src

scibench-matter

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Official source

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