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Problem

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question

HO - OH(g) \rightarrow 2OH (g) ∆H°_diss= 51 Kcal/mole From this value and the following data calculate: (a) ∆H°_fof OH(g). (b) C-O bond energy; ∆H°_dissin CH_3OH(g). ∆H°_fof H_2O_2(g) = \rule{1em}{1pt} 32.58 Kcal/mole. ∆H°_fof CH_3(g) = 34.0 Kcal/mole. ∆H°_fof CH_3OH(g) = \rule{1em}{1pt} 47.96 Kcal/mole.

category

chemistry

options

  1. 14.08 Kcal/mole, 80.45 Kcal/mole
  2. 7.89 Kcal/mole, 95.12 Kcal/mole
  3. 10.50 Kcal/mole, 90.00 Kcal/mole
  4. 11.25 Kcal/mole, 87.65 Kcal/mole
  5. 8.50 Kcal/mole, 92.30 Kcal/mole
  6. 10.11 Kcal/mole, 88.16 Kcal/mole
  7. 13.37 Kcal/mole, 82.79 Kcal/mole
  8. 12.34 Kcal/mole, 85.23 Kcal/mole
  9. 9.21 Kcal/mole, 91.17 Kcal/mole
  10. 8.92 Kcal/mole, 93.21 Kcal/mole

src

stemez-Chemistry

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Source and history

Official source

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