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MMLU-Pro / 4388 / Chromic oxide (Cr_2 O_3) may be reduced with hydrogen according to the equation…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

Chromic oxide (Cr_2 O_3) may be reduced with hydrogen according to the equation Cr_2 O_3 + 3H_2 \rightarrow 2Cr + 3H_2 O (a) What weight of hydrogen would be required to reduce 7.6 g of Cr_2 O_3? (b) For each mole of metallic chromium prepared, how many moles of hydrogen will be required? (c) What weight of metallic chromium can be prepared from one ton of Cr_2 O_3? 1 lb = 454 g.

category

chemistry

options

  1. 0.50 g, 2.5 moles, 1500 lbs
  2. 0.60 g, 3.0 moles, 1600 lbs
  3. 0.30 g, 1.5 moles, 1333 lbs
  4. 0.45 g, 2.25 moles, 1550 lbs
  5. 0.40 g, 2.0 moles, 1400 lbs
  6. 0.10 g, 0.5 moles, 1350 lbs
  7. 0.35 g, 1.75 moles, 1250 lbs
  8. 0.15 g, 0.75 moles, 1300 lbs
  9. 0.20 g, 1.0 moles, 1200 lbs
  10. 0.25 g, 1.25 moles, 1450 lbs

src

stemez-Chemistry

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Source and history

upstream_id / Original problem ID
4388
task_id
7a117aed-addc-5072-84d3-d2f5b44962fa
task_key
default--test--4388
task_revision_id
1
config / split
default / test

Official source

initial import