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MMLU-Pro / 4390 / Calculate the work done when 18.0g of liquid water are vaporized at 100°C…

Problem

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question

Calculate the work done when 18.0g of liquid water are vaporized at 100°C against a constant external pressure of 1.00 atm, given that \DeltaH_vap (H_2O) = 9.7 kcal mole^-1 \DeltaH_fus (H_2O)= 1.4 kcal mole^-1 R= 0.0820 liter atm mole^-1 deg^-1 = 1.99 cal mole^-1 deg^-1 Density of H_2O(l) = 1.00g cm^-3 and molecular wt of water = 18.0 g mol^-1

category

chemistry

options

  1. 650 cal
  2. 540 cal
  3. 500 cal
  4. 742.17 cal
  5. 610 cal
  6. 750 cal
  7. 870 cal
  8. 980 cal
  9. 800 cal
  10. 900 cal

src

stemez-PhysicalChemistry

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Official source

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