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MMLU-Pro / 4437 / A Cu(II) metal ion (giso = 2.12) produces four lines with a separation of 500…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

A Cu(II) metal ion (giso = 2.12) produces four lines with a separation of 500 MHz between each line. Express the hyperfine splitting in field units of mT and the hyperfine coupling in units of wavenumbers.

category

chemistry

options

  1. 500 MHz = 32.953 mT = 0.76298 cm-1
  2. 500 MHz = 40.123 mT = 1.09876 cm-1
  3. 500 MHz = 16.850 mT = 0.01667 cm-1
  4. 500 MHz = 45.672 mT = 2.86329 cm-1
  5. 500 MHz = 70.456 mT = 4.32109 cm-1
  6. 500 MHz = 50.987 mT = 2.34567 cm-1
  7. 500 MHz = 35.789 mT = 1.23456 cm-1
  8. 500 MHz = 60.123 mT = 3.21098 cm-1
  9. 500 MHz = 0.185 mT = 0.29842 cm-1
  10. 500 MHz = 21.234 mT = 0.54321 cm-1

src

ori_mmlu-college_chemistry

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Source and history

upstream_id / Original problem ID
4437
task_id
b2925199-8505-5efa-ab22-751c34c29a8e
task_key
default--test--4437
task_revision_id
1
config / split
default / test

Official source

initial import