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MMLU-Pro / 4488 / Two substances A and B have the same 0.132-atm vapor press-ure at 15°C, but A…

Problem

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question

Two substances A and B have the same 0.132-atm vapor press-ure at 15°C, but A has a heat of vaporization of 25,000 (J / mole), whereas B, 35,000 (J / mole). What will be the respective normal boiling points?

category

chemistry

options

  1. 70.78°C for A and 75.56°C for B
  2. 90.78°C for A and 81.56°C for B
  3. 80.78°C for A and 66.56°C for B
  4. 94.78°C for A and 71.56°C for B
  5. 99.78°C for A and 56.56°C for B
  6. 84.78°C for A and 61.56°C for B
  7. 78.78°C for A and 65.56°C for B
  8. 74.78°C for A and 51.56°C for B
  9. 95.78°C for A and 60.56°C for B
  10. 89.78°C for A and 76.56°C for B

src

stemez-Chemistry

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