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MMLU-Pro / 4549 / At 1000°K, K = 2.37 × 10-^14 for the reaction, N_2 (g) + 3H_2 (g)…

Problem

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question

At 1000°K, K = 2.37 × 10-^14 for the reaction, N_2 (g) + 3H_2 (g) \rightleftarrows 2NH_3 (g) . If you inject one mole of each N_2 and H_2 in a one-liter box at 1000°K, what per cent of the H_2 will be converted to NH_3 at equilibrium?

category

chemistry

options

  1. 10.2%
  2. 6.5%
  3. 8.4%
  4. 3.2%
  5. 5.0%
  6. 18.7%
  7. 15.0%
  8. 12.6%
  9. 22.3%
  10. 2.0%

src

stemez-Chemistry

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Source and history

upstream_id / Original problem ID
4549
task_id
5ef56e5e-5e7b-5a24-938b-f9e6d2d496e5
task_key
default--test--4549
task_revision_id
1
config / split
default / test

Official source

initial import