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MMLU-Pro / 4556 / A lunar module usedAerozine50 as fuel and nitrogen tetroxide (N_2 O_4, molecular…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

A lunar module usedAerozine50 as fuel and nitrogen tetroxide (N_2 O_4, molecular weight = 92.0 g/mole) as oxidizer.Aerozine50 consists of 50 % by weight of hydrazine (N_2 H_4, molecular weight = 32.0 g/mole) and 50 % by weight of unsymmetricaldimethylhydrazine ((CH_3)_2 N_2 H_2, molecular weight = 60.0 g/mole). The chief exhaust product was water (H_2 O, molecular weight = 18.0 g/mole). Two of the reactions that led to the formation of water are the following: 2N_2 H_4 + N_2 O_4\rightarrow3N_2 + 4H_2 O (CH_3)_2 N_2 H_2 + 2N_2 O_4\rightarrow2CO_2 + 3N_2 + 4H_2 O. If we assume that these reactions were the only ones in which water was formed, how much water was produced by the ascent of the lunar module if 2200 kg ofAerozine50 were consumed in the process?

category

chemistry

options

  1. 1.5 × 10^3 kg of water
  2. 3.0 × 10^3 kg of water
  3. 2.5 × 10^3 kg of water
  4. 4.0 × 10^3 kg of water
  5. 1.8 × 10^3 kg of water
  6. 2.2 × 10^3 kg of water
  7. 3.5 × 10^3 kg of water
  8. 2.0 × 10^3 kg of water
  9. 1.0 × 10^3 kg of water
  10. 2.8 × 10^3 kg of water

src

stemez-Chemistry

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Source and history

upstream_id / Original problem ID
4556
task_id
1ad14f29-8a2e-5be2-ba2e-af5e4f98afe9
task_key
default--test--4556
task_revision_id
1
config / split
default / test

Official source

initial import