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MMLU-Pro / 4619 / For the gas-phase decomposition of acetaldehyde, CH_3CHO…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

For the gas-phase decomposition of acetaldehyde, CH_3CHO\rightarrow CH_4 + CO, the second-order rate constant changes from 0.105 m^-1 sec^-1 at 759°K to 0.343 m^-1 sec^-1 at 791°K. Calculate the activation energy that this corresponds to. What rate constant would you predict for 836°K?

category

chemistry

options

  1. 2.2407 × 10^5 J/mole, 2.05 m^-1 sec^-1
  2. 2.5407 × 10^5 J/mole, 1.45 m^-1 sec^-1
  3. 2.0407 × 10^5 J/mole, 1.65 m^-1 sec^-1
  4. 1.9407 × 10^5 J/mole, 1.75 m^-1 sec^-1
  5. 1.8407 × 10^5 J/mole, 2.55 m^-1 sec^-1
  6. 1.6407 × 10^5 J/mole, 0.95 m^-1 sec^-1
  7. 1.8407 × 10^5 J/mole, 1.55 m^-1 sec^-1
  8. 2.8407 × 10^5 J/mole, 1.55 m^-1 sec^-1
  9. 1.7407 × 10^5 J/mole, 2.15 m^-1 sec^-1

src

stemez-Chemistry

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Source and history

upstream_id / Original problem ID
4619
task_id
c21764bd-a84d-5897-9f35-b6b026be17a5
task_key
default--test--4619
task_revision_id
1
config / split
default / test

Official source

initial import