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MMLU-Pro / 4660 / The first step in the radioactive decay of (^238 _92)U is (^238 _92)U = (^234…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

The first step in the radioactive decay of (^238 _92)U is (^238 _92)U = (^234 _90)Th+ (^4 _2)He. Calculate the energy released in this reaction. The exact masses of (^238 _92)U, (^234 _90)Th, and (^4 _2)He are 238.0508, 234.0437 and 4.0026amu, respectively.(1.00073amu= 1.673 × 10^-24 g.)

category

chemistry

options

  1. 3.21 × 10^-6 ergs
  2. 2.98 × 10^-6 ergs
  3. 6.72 × 10^-6 ergs
  4. 5.00 × 10^-6 ergs
  5. 5.55 × 10^-6 ergs
  6. 4.65 × 10^-6 ergs
  7. 7.00 × 10^-6 ergs
  8. 8.44 × 10^-6 ergs
  9. 9.32 × 10^-6 ergs
  10. 7.89 × 10^-6 ergs

src

stemez-PhysicalChemistry

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Source and history

upstream_id / Original problem ID
4660
task_id
d42ae0d4-a6c5-5c89-919f-e23bec4bfa1d
task_key
default--test--4660
task_revision_id
1
config / split
default / test

Official source

initial import