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MMLU-Pro / 789 / At the Harris foundry, the total daily cost of manufacturing m pieces of metal…

Problem

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question

At the Harris foundry, the total daily cost of manufacturing m pieces of metal is represented by the following equation: C (in dollars) = 3 m^2 + m + 9. If the cost of the work produced by 9:00 am is $4,849 and the rate of manufacture after 9:00 am is 10 pieces per hr., (i) how many pieces of metal will have been produced by lunch hour (12 noon)? Hint: use the quadratic formula: m = [{- b \pm \surd(b^2 - 4ac)} / {2a}], and other calculations. (ii) When t represents the number of hours past 9:00 am., express the total cost as a function of t.

category

business

options

  1. 90 pieces
  2. 50 pieces
  3. 60 pieces
  4. 100 pieces
  5. 95 pieces
  6. 70 pieces
  7. 85 pieces
  8. 65 pieces
  9. 75 pieces
  10. 80 pieces

src

stemez-Business

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Source and history

upstream_id / Original problem ID
789
task_id
e5b8ebe4-bdcf-5154-97f0-78a1d033df9f
task_key
default--test--789
task_revision_id
1
config / split
default / test

Official source

initial import