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MMLU-Pro / 7971 / H(z) = ∫₀¹e^(−z²t²)dt, what is H'(1)?

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

H(z) = ∫01e−z2t2dt\int_0^1 e^{-z^2 t^2} dt, what is H'(1)?
Plain-text mathematical notation (without MathML)
H(z) = ∫₀¹e^(−z²t²)dt, what is H'(1)?
Original LaTeX notation
H(z) = $\int_0^1 e^{-z^2 t^2} dt$, what is H'(1)?

category

math

options

  1. -2.3789
  2. 1.0000
  3. -0.3789
  4. -0.7461
  5. 0
  6. -1.3789
  7. 0.3789
  8. 1.3789
  9. 0.7461
  10. 2.3789

src

theoremQA-Math

Discussion

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Source and history

upstream_id / Original problem ID
7971
task_id
ec14f5cd-efa2-5dfd-88d0-61f0e04a543d
task_key
default--test--7971
task_revision_id
1
config / split
default / test

Official source

initial import