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MMLU-Pro / 9233 / A particle of charge +3.00×10^(−6)C is 12.0 mathrm{~cm}…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

A particle of charge +3.00×10−6C+3.00 \times 10^{-6} \mathrm{C} is $12.0 \mathrm{~cm}$ distant from a second particle of charge −1.50×10−6C-1.50 \times 10^{-6} \mathrm{C}. Calculate the magnitude of the electrostatic force between the particles.
Plain-text mathematical notation (without MathML)
A particle of charge +3.00×10^(−6)C is $12.0 \mathrm{~cm}$ distant from a second particle of charge −1.50×10^(−6)C. Calculate the magnitude of the electrostatic force between the particles.
Original LaTeX notation
A particle of charge $+3.00 \times 10^{-6} \mathrm{C}$ is $12.0 \mathrm{~cm}$ distant from a second particle of charge $-1.50 \times 10^{-6} \mathrm{C}$. Calculate the magnitude of the electrostatic force between the particles.

category

physics

options

  1. 3.42 N
  2. 1.56 N
  3. 0.92 N
  4. 5.00 N
  5. 2.35 N
  6. 4.50 N
  7. 3.67 N
  8. 2.81 N
  9. 1.23 N
  10. 0.75 N

src

scibench-fund

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Source and history

upstream_id / Original problem ID
9233
task_id
6c403a32-2881-5b02-ab70-88809a9ed352
task_key
default--test--9233
task_revision_id
1
config / split
default / test

Official source

initial import