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Problem

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question

A sonar device emits waves of frequency 40,000 cycles\bullet s^-1. The velocities of the wave in air and water are 1100 ft \bullet s^-1 and 4200 ft \bullet s^-1, respectively. What are the frequency of the wave in air and the wavelengths in air and water? Suppose that the device is fixed to the bottom of a ship. It emits a signal and the echo from the ocean bed returns 0.8 s later. What is the depth of the ocean at that point?

category

physics

options

  1. Frequency in air: 40,000 cycles/s, Wavelength in air: 3.00 × 10^-2 ft, Wavelength in water: 9.00 × 10^-2 ft, Ocean depth: 1650 ft
  2. Frequency in air: 50,000 cycles/s, Wavelength in air: 3.75 × 10^-2 ft, Wavelength in water: 11.50 × 10^-2 ft, Ocean depth: 1750 ft
  3. Frequency in air: 45,000 cycles/s, Wavelength in air: 2.85 × 10^-2 ft, Wavelength in water: 12.50 × 10^-2 ft, Ocean depth: 1700 ft
  4. Frequency in air: 38,000 cycles/s, Wavelength in air: 2.90 × 10^-2 ft, Wavelength in water: 11.00 × 10^-2 ft, Ocean depth: 1760 ft
  5. Frequency in air: 40,000 cycles/s, Wavelength in air: 2.50 × 10^-2 ft, Wavelength in water: 12.00 × 10^-2 ft, Ocean depth: 1600 ft
  6. Frequency in air: 30,000 cycles/s, Wavelength in air: 1.75 × 10^-2 ft, Wavelength in water: 9.50 × 10^-2 ft, Ocean depth: 1600 ft
  7. Frequency in air: 40,000 cycles/s, Wavelength in air: 2.75 × 10^-2 ft, Wavelength in water: 10.50 × 10^-2 ft, Ocean depth: 1680 ft
  8. Frequency in air: 35,000 cycles/s, Wavelength in air: 3.14 × 10^-2 ft, Wavelength in water: 11.90 × 10^-2 ft, Ocean depth: 1720 ft
  9. Frequency in air: 42,000 cycles/s, Wavelength in air: 2.60 × 10^-2 ft, Wavelength in water: 10.20 × 10^-2 ft, Ocean depth: 1620 ft
  10. Frequency in air: 40,000 cycles/s, Wavelength in air: 2.85 × 10^-2 ft, Wavelength in water: 8.50 × 10^-2 ft, Ocean depth: 1700 ft

src

stemez-Physics

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