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question

Digital images consist of a very large number of equally spaced dots called pixels The resolution of an image is the number of pixels/cm in each of the horizontal and vertical directions. Thus, an image with dimensions $10 \mathrm{~cm}$ by $15 \mathrm{~cm}$ and a resolution of 75 pixels/cm has a total of (10×75)×(15×75)=843750(10 \times 75) \times(15 \times 75)=843750 pixels. If each of these dimensions was increased by n%n \% and the resolution was decreased by n%n \%, the image would have 345600 pixels. Determine the value of nn.
Plain-text mathematical notation (without MathML)
Digital images consist of a very large number of equally spaced dots called pixels The resolution of an image is the number of pixels/cm in each of the horizontal and vertical directions.

Thus, an image with dimensions $10 \mathrm{~cm}$ by $15 \mathrm{~cm}$ and a resolution of 75 pixels/cm has a total of (10×75)×(15×75)=843750 pixels.

If each of these dimensions was increased by n% and the resolution was decreased by n%, the image would have 345600 pixels.

Determine the value of n.
Original LaTeX notation
Digital images consist of a very large number of equally spaced dots called pixels The resolution of an image is the number of pixels/cm in each of the horizontal and vertical directions.

Thus, an image with dimensions $10 \mathrm{~cm}$ by $15 \mathrm{~cm}$ and a resolution of 75 pixels/cm has a total of $(10 \times 75) \times(15 \times 75)=843750$ pixels.

If each of these dimensions was increased by $n \%$ and the resolution was decreased by $n \%$, the image would have 345600 pixels.

Determine the value of $n$.

answer type

Numerical

is multiple answer

false

language

English

question type

Open-ended

subject

Math

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