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Omni-MATH / Let P be a point inside regular pentagon ABCDE such that ∠PAB=48^(∘) and ∠PDC=42^(∘). Find ∠BPC, in degrees.

Problem

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problem

Let PP be a point inside regular pentagon ABCDEA B C D E such that ∠PAB=48∘\angle P A B=48^{\circ} and ∠PDC=42∘\angle P D C=42^{\circ}. Find ∠BPC\angle B P C, in degrees.
Plain-text mathematical notation (without MathML)
Let P be a point inside regular pentagon ABCDE such that ∠PAB=48^(∘) and ∠PDC=42^(∘). Find ∠BPC, in degrees.
Original LaTeX notation
Let $P$ be a point inside regular pentagon $A B C D E$ such that $\angle P A B=48^{\circ}$ and $\angle P D C=42^{\circ}$. Find $\angle B P C$, in degrees.

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Source and history

task_id
121cf07b-56ec-5800-b736-51ee696089c0
task_key
test--121cf07b-56ec-5800-b736-51ee696089c0
task_revision_id
1
config / split
/ test

Official source

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